Tuesday, 4 August 2015

What is the output of following program?

  1. package com.javastepbystep;

  2. class A
  3. {
  4.  
  5.      static int method1(int i)
  6.     {
  7.          return method2(i *= 11);
  8.      }
  9.  
  10.       static int method2(int i)
  11.      {
  12.           return method3(i /= 11);
  13.       }
  14.  
  15.        static int method3(int i)
  16.       {
  17.            return method4(i -= 11);
  18.       }
  19.  
  20.       static int method4(int i)
  21.      {
  22.          return i += 11;
  23.      }
         
  24.      public static void main(String [] args)
  25.     {
  26.           System.out.println(method1(11));
  27.      }
  28.  
  29. }

Ans: 11

Sunday, 2 August 2015

What is the output of following program?

 public class B{
    
      B b= new B();
    
     public int show(){
          return (true ? null : 0);
     }
    
     public static void main(String[] args)  {
    
            B b= new B();
            b.show();
        }
    
    }

Output:
  1. Exception in thread "main" java.lang.StackOverflowError
  2. at com.instanceofjava.B.<init>(B.java:3)
  3. at com.instanceofjava.B.<init>(B.java:5)
  4. at com.instanceofjava.B.<init>(B.java:5) 

Explanation:

  • Whenever we create the object of any class constructor will be called first and memory allocated for all non-static variables
  • Here  B b= new B(); the variable is an object and assigned to a new object of the same class
  • B b= new B(); statement leads to recursive execution of constructor will create infinite objects so at the run time an exception will be raised
  • Exception in thread "main" java.lang.StackOverflowError
  • The common cause for a stack overflow exception is a bad recursive call. Typically this is caused when your recursive functions don't have the correct termination condition

Thursday, 30 July 2015

What will be the output of java program

public class Test {
    public static void main(String[] args) {
        System.out.println(Math.min(Double.MIN_VALUE, 0.0d));
    }
}
Answer: 

This question is tricky because unlike the Integer, where MIN_VALUE is negative, both the MAX_VALUE and MIN_VALUE of the Double class are positive numbers.

The Double.MIN_VALUE is 2^(-1074), a double constant whose magnitude is the least among all double values. So unlike the obvious answer, this program will print 0.0 because of Double.MIN_VALUE is greater than 0.

Difference between == and .equals()

They both differ very much in their significance. equals() method is present in the java.lang.Object class and it is expected to check for the equivalence of the state of objects! That means, the contents of the objects.

Whereas the '==' operator is expected to check the actual object instances are same or not.

For example, lets say, you have two String objects and they are being pointed by two different reference variables s1 and s2.


 s1 = new String("abc");
 s2 = new String("abc");

Now, if you use the "equals()" method to check for their equivalence as


 if(s1.equals(s2))
      System.out.println("s1.equals(s2) is TRUE");
 else
      System.out.println("s1.equals(s2) is FALSE");
You will get the output as TRUE as the 'equals()' method check for the content equivality.

Lets check the '==' operator.


if(s1==s2)
     System.out.printlln("s1==s2 is TRUE");
   else
     System.out.println("s1==s2 is FALSE");

Now you will get the FALSE as output because both s1 and s2 are pointing to two different objects even though both of them share the same string content.

It is because of 'new String()' everytime a new object is created.

Try running the program without 'new String' and just with


   String s1 = "abc";
   String s2 = "abc";

You will get TRUE for both the tests.

Monday, 13 July 2015

Java Creating a Thread

In the most general sense, you create a thread by instantiating an object of type Thread. Java identifies two ways in which this can be accomplished:

(i) You can implement the Runnable interface.

(ii) You can extend the Thread class, itself.

1. Implementing Runnable


The easiest way to create a thread is to create a class that implements the Runnable interface. To implement Runnable, a class need only implement a single method called run():

public void run()

Inside the run() method, you will define the code that constitutes the new thread. The run() can call other methods, use other classes and declare variables, just like the main thread.

The only difference is that run() establishes the entry point for another, concurrent thread of execution within your program. This thread will end when run() returns.

After you create a class that implements Runnable, you will instantiate an object of type Thread from within that class using one of the following constructors:

Thread(Runnable threadObj)

Thread(Runnable threadObj, String threadName)

Here threadObj is the object whose run method is called and threadName is the name of the new thread.

After the new thread is created, it will not start running until you call start() method. The start() method puts the thread in the ready queue (runnable state). Whenever the thread gets scheduled its execution will start from the run() method.

Example:

class X implements Runnable
      public void run()
     { 
          for(int i=1; i<=5; i++)
          { 
               System.out.println("Child Thread: " + I);
          }

          System.out.println("Exiting child thread");

      }

}

class RunnableTest
     public static void main(String args[])
     { 
         X runnable  = new X();

         Thread ct = new Thread(runnable);

          ct.start();

          System.out.println("main thread exiting");

      }

}

Output:

main thread exiting

Child Thread: 1

Child Thread: 2

Child Thread: 3

Child Thread: 4

Child Thread: 5

Exiting child thread

Example:

class NewThread implements Runnable
     Thread t;

      NewThread()
     { 
         t = new Thread(this, "Demo Thread");

         System.out.println("Child thread: " + t);

         t.start();

     }

     public void run()
     { 
           for(int i=5; i>0; i--)
           {
                 try
                 { 
                       System.out.println("Child Thread: " + I);
                 }
                 catch(InterruptedException e)
                { 
                     System.out.println(e);
                }
      }

      System.out.println("Exiting child thread”);

      Thread.sleep(500);

    }

}

class ThreadDemo
     public static void main(String args[])
    { 
          new NewThread();
          try
          { 
               for(int n=5; n>0; n--)
               {
                   System.out.println("Main Thread: " + n);
                   Thread.sleep(1000);
               }
           }
           catch(InterruptedException e)
           {
                System.out.println("main thread interrupted");
            }
           System.out.println("main thread exiting");
     }
}

Output:

Child thread: Thread[Demo Thread,5,main]

Main Thread: 5

Child Thread: 5

Child Thread: 4

Main Thread: 4

Child Thread: 3

Child Thread: 2

Main Thread: 3

Child Thread: 1

Exiting child thread

Main Thread: 2

Main Thread: 1

main thread exiting

2. Extending Thread class

The second way to create a thread is to create a new class that extends Thread and then create an instance of that class. The extending class must override the run() method, which is the entry point for the new thread. It must also call start() to begin the execution of the new thread.

Example:

public class NewThread extends Thread
     NewThread()
     { 
            super("Demo Thread");
            System.out.println("Child thread: " + this);
            start();
      }

      public void run()
      { 
          for(int i=5; i>0; i--)
          { 
              try
              {
                  System.out.println("Child Thread: " + I);
                  sleep(500);
              }
              catch(InterruptedException e)
              {

              }

          }
          System.out.println("Exiting child thread");
          System.out.println(e);
     }
}

class ExtendThread
        public static void main(String args[])
        { 
            new NewThread();
            try
            { 
                for(int n=5; n>0; n--)
                {
                     System.out.println("Main Thread: " + n);
                     Thread.sleep(1000);
                }
             }
            catch(InterruptedException e)
            {
                 System.out.println("main thread interrupted");
            }
            System.out.println("main thread exiting");
       }
}

Output:

Child thread: Thread[Demo Thread,5,main]

Main Thread: 5

Child Thread: 5

Child Thread: 4

Main Thread: 4

Child Thread: 3

Child Thread: 2

Main Thread: 3

Child Thread: 1

Exiting child thread

Main Thread: 2

Main Thread: 1

main thread exiting

Note: If the thread is not assigned any name, it will be something like Thread-1, Thread-2, Thread-3 etc.

3. Choosing an Approach

The thread class defines several methods that can be overridden by a derived class. Out of these methods, the only one that must be overridden is run().

That is, of course, the same method required when you implement the Runnable interface. Many Java programmers feel that classes should be extended only when they are being enhanced or modified in some way.

So, if you will not be overriding any of Thread’s other methods, it is probably best simply to implement a Runnable interface.